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13-(e)

図 6: (e)
\includegraphics[width=5.00truecm,scale=1.1]{e.eps}

13-(e)解答

$\displaystyle (q_j,\vr_j)=\left(q,1,1\right),\,\left(q,-1,1\right),\,\left(-q,-1,-1\right),\,\left(-q,1,-1\right) $

$\displaystyle {\bf d}= \begin{pmatrix}q-q+q-q \\ q+q+q+q \end{pmatrix}= \begin... ... q-q-q+q & q+q-q-q \end{pmatrix}=\begin{pmatrix} 0 & 0 \\ 0 & 0 \end{pmatrix}$


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著者: 茅根裕司 chinone_at_astr.tohoku.ac.jp