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13-(d)

図 5: (d)
\includegraphics[width=5.00truecm,scale=1.1]{d.eps}

13-(d)解答

$\displaystyle (q_j,\vr_j)=\left(-q,1,0\right),\,\left(q,0,1\right),\,\left(-q,-1,0\right),\,\left(q,0,-1\right) $

$\displaystyle {\bf d}= \begin{pmatrix}-q+q \\ q-q \end{pmatrix}= \begin{pmatri... ... 0 \\ 0 & q+q \end{pmatrix}=\begin{pmatrix} -2q & 0 \\ 0 & 2q \end{pmatrix}$


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著者: 茅根裕司 chinone_at_astr.tohoku.ac.jp