Subsections

13-(f)

図 7: (f)
\includegraphics[width=5.00truecm,scale=1.1]{f.eps}

13-(f)解答

$\displaystyle (q_j,\vr_j)=\left(q,1,1\right),\,\left(-q,-1,1\right),\,\left(q,-1,-1\right),\,\left(-q,1,-1\right)
$

$\displaystyle {\bf d}= \begin{pmatrix}q+q-q-q \\  q-q-q+q \end{pmatrix}= \begin...
...+q+q+q & q-q+q-q
\end{pmatrix}=\begin{pmatrix}
0 & 4q \\
4q & 0
\end{pmatrix}$

著者: 茅根裕司 chinone_at_astr.tohoku.ac.jp