Subsections

8-(h)

図 14: (h)
\includegraphics[width=5.00truecm,scale=1.1]{h.eps}

8-(h)解答

$\displaystyle (q_j,\vr_j)=\left(q,1,0\right),\,\left(q,0,1\right),\,\left(q,-1,0\right),\,\left(q,0,-1\right)
$

$\displaystyle {\bf d}= \begin{pmatrix}q-q \\  q-q \end{pmatrix}= \begin{pmatrix...
...& 0 \\
0 & q+q
\end{pmatrix}=\begin{pmatrix}
2q & 0 \\
0 & 2q
\end{pmatrix}$

著者: 茅根裕司 chinone_at_astr.tohoku.ac.jp