Subsections

8-(a)

図 7: (a)
\includegraphics[width=5.00truecm,scale=1.1]{a.eps}

8-(a)解答

$\displaystyle (q_j,\vr_j)=\left(q,1,0\right),\,\left(-q,-1,0\right)
$

$\displaystyle {\bf d}= \begin{pmatrix}q+q \\  0 \end{pmatrix}= \begin{pmatrix}2...
...q-q & 0 \\
0 & 0
\end{pmatrix}=\begin{pmatrix}
0 & 0 \\
0 & 0
\end{pmatrix}$

著者: 茅根裕司 chinone_at_astr.tohoku.ac.jp