6-1

$B_0=1\,[{\rm\mu G}]$の時、Electron cyclotron frequency

$$\omega_{{\rm ce}} = \frac{eB_0}{m_e c}$$ (32)

を求めよ。

6-1解答

$$\quad \mu_B = \frac{e\hbar}{2m_e} = 5.788381804 \times 10^{-11}\,[{\rm MeV\,T^{-1}}]$$ (33)

$$1\,[{\rm eV}] = 2\pi \cdot 2.41798949 \times 10^{14}\,[{\rm Hz}]$$ (34)

$$\omega_{{\rm ce}} = \frac{eB_0}{m_e c} =\frac{\mu_B}{\dfrac{e\hbar}{2m_e}} \frac{eB_0}{m_e} =2 \mu_B B_0$$

$$= 2\cdot \left( 5.788381804 \times 10^{-11} \times 10^6 \right) \... ...10^{14} \right) \cdot 10^{-4} \,\left( B_0\,[{\rm\mu G}]\right)\quad [{\rm Hz}]$$

$$=17.5882 \,\left( B_0\,[{\rm\mu G}]\right)\quad [{\rm Hz}]$$ (35)

著者: 茅根裕司 chinone_at_astr.tohoku.ac.jp