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13-(b)

図 3: (b)
\includegraphics[width=5.00truecm,scale=1.1]{b.eps}

13-(b)解答

$\displaystyle (q_j,\vr_j)=\left(q,1,0\right),\,\left(q,-1,0\right) $

$\displaystyle {\bf d}= \begin{pmatrix}q-q \\ 0 \end{pmatrix}= \begin{pmatrix}0... ...+q & 0 \\ 0 & 0 \end{pmatrix}=\begin{pmatrix} 2q & 0 \\ 0 & 0 \end{pmatrix}$


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著者: 茅根裕司 chinone_at_astr.tohoku.ac.jp