Subsections

3-1

$\displaystyle \Nabla \times \left( \Nabla \times \vA\right) = \Nabla \left( \Nabla \cdot \vA\right) - \Nabla^2 \vA$ (6)

を示せ。

3-1解答

$\displaystyle \Nabla \times \left( \Nabla \times \vA\right)$ $\displaystyle = \left( \ve_i \partial_i\right) \times \left\{ \left( \ve_j \par...
...\right)\partial_{ij}A_k =\vepsilon_{jkl}\vepsilon_{ilm} \ve_m \partial_{ij} A_k$    
  $\displaystyle =-\vepsilon_{jkl}\vepsilon_{iml} \ve_{m} \partial_{ij} A_k = -\le...
..._{ki}\ve_{m} \partial_{ij} A_k -\delta_{ji}\delta_{km}\ve_{m} \partial_{ij} A_k$    
  $\displaystyle =\ve_m \partial_{mk}A_k -\partial_{ii}\left(A_k\ve_k\right) =\Nabla\left(\Nabla\cdot \vA\right) -\Nabla^2 \vA$    

著者: 茅根裕司 chinone_at_astr.tohoku.ac.jp